Base | Representation |
---|---|
bin | 11111010101001011111… |
… | …111000010011001110101 |
3 | 21121211101222212202021222 |
4 | 133111023333002121311 |
5 | 240233423134301123 |
6 | 4325033223120125 |
7 | 311360446130513 |
oct | 37251377023165 |
9 | 7554358782258 |
10 | 2153053431413 |
11 | 760117594175 |
12 | 2a93392a3045 |
13 | 1280555b5281 |
14 | 762cb9954b3 |
15 | 3b014ba76c8 |
hex | 1f54bfc2675 |
2153053431413 has 2 divisors, whose sum is σ = 2153053431414. Its totient is φ = 2153053431412.
The previous prime is 2153053431409. The next prime is 2153053431493. The reversal of 2153053431413 is 3141343503512.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2152508582449 + 544848964 = 1467143^2 + 23342^2 .
It is a cyclic number.
It is not a de Polignac number, because 2153053431413 - 22 = 2153053431409 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2153053431493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076526715706 + 1076526715707.
It is an arithmetic number, because the mean of its divisors is an integer number (1076526715707).
Almost surely, 22153053431413 is an apocalyptic number.
It is an amenable number.
2153053431413 is a deficient number, since it is larger than the sum of its proper divisors (1).
2153053431413 is an equidigital number, since it uses as much as digits as its factorization.
2153053431413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 2153053431413 its reverse (3141343503512), we get a palindrome (5294396934925).
The spelling of 2153053431413 in words is "two trillion, one hundred fifty-three billion, fifty-three million, four hundred thirty-one thousand, four hundred thirteen".
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