Base | Representation |
---|---|
bin | 1001110010100111110000… |
… | …10000011000000101101101 |
3 | 2211020022002102121210200201 |
4 | 10321103320100120011231 |
5 | 10310224022012130333 |
6 | 113442554414153501 |
7 | 4351346610666022 |
oct | 471237020300555 |
9 | 84208072553621 |
10 | 21530541130093 |
11 | 6951062193506 |
12 | 24b891a7b2891 |
13 | c02423c18548 |
14 | 546125b53549 |
15 | 2750d35e917d |
hex | 1394f841816d |
21530541130093 has 2 divisors, whose sum is σ = 21530541130094. Its totient is φ = 21530541130092.
The previous prime is 21530541130031. The next prime is 21530541130099. The reversal of 21530541130093 is 39003114503512.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15992976770884 + 5537564359209 = 3999122^2 + 2353203^2 .
It is a cyclic number.
It is not a de Polignac number, because 21530541130093 - 241 = 19331517874541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21530541130099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10765270565046 + 10765270565047.
It is an arithmetic number, because the mean of its divisors is an integer number (10765270565047).
Almost surely, 221530541130093 is an apocalyptic number.
It is an amenable number.
21530541130093 is a deficient number, since it is larger than the sum of its proper divisors (1).
21530541130093 is an equidigital number, since it uses as much as digits as its factorization.
21530541130093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48600, while the sum is 37.
The spelling of 21530541130093 in words is "twenty-one trillion, five hundred thirty billion, five hundred forty-one million, one hundred thirty thousand, ninety-three".
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