Base | Representation |
---|---|
bin | 110000111101001100010100… |
… | …100110010110001101011110 |
3 | 1001020100120020021000201122201 |
4 | 300331030110212112031132 |
5 | 211210130121341100132 |
6 | 2041532400314002114 |
7 | 63231505666352326 |
oct | 6075142446261536 |
9 | 1036316207021581 |
10 | 215311351112542 |
11 | 62672038602a73 |
12 | 20194947a1633a |
13 | 931aa08bba2a9 |
14 | 3b251a6dc8286 |
15 | 19d5b206aa2e7 |
hex | c3d31499635e |
215311351112542 has 4 divisors (see below), whose sum is σ = 322967026668816. Its totient is φ = 107655675556270.
The previous prime is 215311351112519. The next prime is 215311351112591. The reversal of 215311351112542 is 245211153113512.
215311351112542 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×2153113511125422 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53827837778134 + ... + 53827837778137.
It is an arithmetic number, because the mean of its divisors is an integer number (80741756667204).
Almost surely, 2215311351112542 is an apocalyptic number.
215311351112542 is a deficient number, since it is larger than the sum of its proper divisors (107655675556274).
215311351112542 is a wasteful number, since it uses less digits than its factorization.
215311351112542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107655675556273.
The product of its digits is 36000, while the sum is 37.
The spelling of 215311351112542 in words is "two hundred fifteen trillion, three hundred eleven billion, three hundred fifty-one million, one hundred twelve thousand, five hundred forty-two".
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