Base | Representation |
---|---|
bin | 1100100010000110101… |
… | …1001001100001100011 |
3 | 202120202120000011002102 |
4 | 3020201223021201203 |
5 | 12011430202333011 |
6 | 242525155441015 |
7 | 21361444025603 |
oct | 3104153114143 |
9 | 676676004072 |
10 | 215313324131 |
11 | 8334a838284 |
12 | 3588bbb616b |
13 | 173c4a4c909 |
14 | a5c7b86c03 |
15 | 5902a2a73b |
hex | 3221ac9863 |
215313324131 has 24 divisors (see below), whose sum is σ = 228038746752. Its totient is φ = 203083430400.
The previous prime is 215313324119. The next prime is 215313324133. The reversal of 215313324131 is 131423313512.
It is not a de Polignac number, because 215313324131 - 234 = 198133454947 is a prime.
It is a super-2 number, since 2×2153133241312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 215313324094 and 215313324103.
It is not an unprimeable number, because it can be changed into a prime (215313324133) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 91349405 + ... + 91351761.
It is an arithmetic number, because the mean of its divisors is an integer number (9501614448).
Almost surely, 2215313324131 is an apocalyptic number.
215313324131 is a deficient number, since it is larger than the sum of its proper divisors (12725422621).
215313324131 is a wasteful number, since it uses less digits than its factorization.
215313324131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4223 (or 4182 counting only the distinct ones).
The product of its digits is 6480, while the sum is 29.
Adding to 215313324131 its reverse (131423313512), we get a palindrome (346736637643).
The spelling of 215313324131 in words is "two hundred fifteen billion, three hundred thirteen million, three hundred twenty-four thousand, one hundred thirty-one".
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