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2153146561333 is a prime number
BaseRepresentation
bin11111010101010001100…
…010010011001100110101
321121211122111010020112021
4133111101202103030311
5240234121004430313
64325050351153141
7311362656540355
oct37252142231465
97554574106467
102153146561333
11760165113049
122a93645157b1
1312806b991a31
14762da0b8b65
153b01ce5178d
hex1f551893335

2153146561333 has 2 divisors, whose sum is σ = 2153146561334. Its totient is φ = 2153146561332.

The previous prime is 2153146561303. The next prime is 2153146561417. The reversal of 2153146561333 is 3331656413512.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1238984931409 + 914161629924 = 1113097^2 + 956118^2 .

It is a cyclic number.

It is not a de Polignac number, because 2153146561333 - 225 = 2153113006901 is a prime.

It is a super-2 number, since 2×21531465613332 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2153146561333.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2153146561303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076573280666 + 1076573280667.

It is an arithmetic number, because the mean of its divisors is an integer number (1076573280667).

Almost surely, 22153146561333 is an apocalyptic number.

It is an amenable number.

2153146561333 is a deficient number, since it is larger than the sum of its proper divisors (1).

2153146561333 is an equidigital number, since it uses as much as digits as its factorization.

2153146561333 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 583200, while the sum is 43.

The spelling of 2153146561333 in words is "two trillion, one hundred fifty-three billion, one hundred forty-six million, five hundred sixty-one thousand, three hundred thirty-three".