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215325351013 = 1875071148359
BaseRepresentation
bin1100100010001001100…
…1000001110001100101
3202120210101122011212111
43020202121001301211
512011441242213023
6242530305321021
721361651166443
oct3104231016145
9676711564774
10215325351013
1183356602253
1235894036171
13173c73a0c06
14a5c95d7b93
155903b0400d
hex3222641c65

215325351013 has 4 divisors (see below), whose sum is σ = 215326686880. Its totient is φ = 215324015148.

The previous prime is 215325350959. The next prime is 215325351019. The reversal of 215325351013 is 310153523512.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 215325351013 - 233 = 206735416421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (215325351019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 386673 + ... + 761686.

It is an arithmetic number, because the mean of its divisors is an integer number (53831671720).

Almost surely, 2215325351013 is an apocalyptic number.

It is an amenable number.

215325351013 is a deficient number, since it is larger than the sum of its proper divisors (1335867).

215325351013 is a wasteful number, since it uses less digits than its factorization.

215325351013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1335866.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 215325351013 its reverse (310153523512), we get a palindrome (525478874525).

The spelling of 215325351013 in words is "two hundred fifteen billion, three hundred twenty-five million, three hundred fifty-one thousand, thirteen".

Divisors: 1 187507 1148359 215325351013