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2153314153 = 17911120223
BaseRepresentation
bin1000000001011000…
…1111011101101001
312120001211200201001
42000112033131221
513402222023103
6553400555001
7104234603554
oct20026173551
95501750631
102153314153
11a05542881
12501182a61
132841668b3
14165da769b
15c909901d
hex8058f769

2153314153 has 4 divisors (see below), whose sum is σ = 2153452288. Its totient is φ = 2153176020.

The previous prime is 2153314151. The next prime is 2153314181. The reversal of 2153314153 is 3514133512.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2153314153 - 21 = 2153314151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2153314151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42201 + ... + 78022.

It is an arithmetic number, because the mean of its divisors is an integer number (538363072).

Almost surely, 22153314153 is an apocalyptic number.

It is an amenable number.

2153314153 is a deficient number, since it is larger than the sum of its proper divisors (138135).

2153314153 is a wasteful number, since it uses less digits than its factorization.

2153314153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 138134.

The product of its digits is 5400, while the sum is 28.

The square root of 2153314153 is about 46403.8161469507. The cubic root of 2153314153 is about 1291.3257114163.

Adding to 2153314153 its reverse (3514133512), we get a palindrome (5667447665).

The spelling of 2153314153 in words is "two billion, one hundred fifty-three million, three hundred fourteen thousand, one hundred fifty-three".

Divisors: 1 17911 120223 2153314153