Base | Representation |
---|---|
bin | 11111010101100001011… |
… | …100010111111011100111 |
3 | 21121212100002022020202200 |
4 | 133111201130113323213 |
5 | 240240142320141203 |
6 | 4325133043305543 |
7 | 311402410154043 |
oct | 37254134277347 |
9 | 7555302266680 |
10 | 2153413443303 |
11 | 760291827461 |
12 | 2a941997b2b3 |
13 | 1280b2065565 |
14 | 7632370b023 |
15 | 3b0365bc9a3 |
hex | 1f561717ee7 |
2153413443303 has 6 divisors (see below), whose sum is σ = 3110486084784. Its totient is φ = 1435608962196.
The previous prime is 2153413443287. The next prime is 2153413443317. The reversal of 2153413443303 is 3033443143512.
2153413443303 is a `hidden beast` number, since 2 + 1 + 5 + 3 + 4 + 1 + 344 + 3 + 303 = 666.
It is not a de Polignac number, because 2153413443303 - 24 = 2153413443287 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2153413443353) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 119634080175 + ... + 119634080192.
It is an arithmetic number, because the mean of its divisors is an integer number (518414347464).
Almost surely, 22153413443303 is an apocalyptic number.
2153413443303 is a deficient number, since it is larger than the sum of its proper divisors (957072641481).
2153413443303 is a wasteful number, since it uses less digits than its factorization.
2153413443303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 239268160373 (or 239268160370 counting only the distinct ones).
The product of its (nonzero) digits is 155520, while the sum is 36.
Adding to 2153413443303 its reverse (3033443143512), we get a palindrome (5186856586815).
The spelling of 2153413443303 in words is "two trillion, one hundred fifty-three billion, four hundred thirteen million, four hundred forty-three thousand, three hundred three".
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