Base | Representation |
---|---|
bin | 110000111101110101010110… |
… | …110010110101001000101000 |
3 | 1001020111202221220010220120002 |
4 | 300331311112302311020220 |
5 | 211211340340301313102 |
6 | 2042004524333522132 |
7 | 63234625565261246 |
oct | 6075652662651050 |
9 | 1036452856126502 |
10 | 215355411354152 |
11 | 62689798450693 |
12 | 201a13a3643348 |
13 | 9321c0b1c4184 |
14 | 3b2738690b796 |
15 | 19d6d4d866902 |
hex | c3dd56cb5228 |
215355411354152 has 32 divisors (see below), whose sum is σ = 403850252822400. Its totient is φ = 107662011614784.
The previous prime is 215355411354101. The next prime is 215355411354163. The reversal of 215355411354152 is 251453114553512.
215355411354152 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 215355411354097 and 215355411354106.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2577305558 + ... + 2577389114.
It is an arithmetic number, because the mean of its divisors is an integer number (12620320400700).
Almost surely, 2215355411354152 is an apocalyptic number.
It is an amenable number.
215355411354152 is a deficient number, since it is larger than the sum of its proper divisors (188494841468248).
215355411354152 is a wasteful number, since it uses less digits than its factorization.
215355411354152 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 126665 (or 126661 counting only the distinct ones).
The product of its digits is 1800000, while the sum is 47.
The spelling of 215355411354152 in words is "two hundred fifteen trillion, three hundred fifty-five billion, four hundred eleven million, three hundred fifty-four thousand, one hundred fifty-two".
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