Base | Representation |
---|---|
bin | 11111010101101111101… |
… | …010111111011101001111 |
3 | 21121212221201111010100112 |
4 | 133111233222333131033 |
5 | 240241134422444424 |
6 | 4325212451550235 |
7 | 311411336166113 |
oct | 37255752773517 |
9 | 7555851433315 |
10 | 2153652156239 |
11 | 7603a4550a81 |
12 | 2a94858bb37b |
13 | 12811c65560c |
14 | 763472c9743 |
15 | 3b04c52260e |
hex | 1f56fabf74f |
2153652156239 has 2 divisors, whose sum is σ = 2153652156240. Its totient is φ = 2153652156238.
The previous prime is 2153652156223. The next prime is 2153652156247. The reversal of 2153652156239 is 9326512563512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2153652156239 - 24 = 2153652156223 is a prime.
It is a super-2 number, since 2×21536521562392 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2153652153239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076826078119 + 1076826078120.
It is an arithmetic number, because the mean of its divisors is an integer number (1076826078120).
Almost surely, 22153652156239 is an apocalyptic number.
2153652156239 is a deficient number, since it is larger than the sum of its proper divisors (1).
2153652156239 is an equidigital number, since it uses as much as digits as its factorization.
2153652156239 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2916000, while the sum is 50.
The spelling of 2153652156239 in words is "two trillion, one hundred fifty-three billion, six hundred fifty-two million, one hundred fifty-six thousand, two hundred thirty-nine".
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