Base | Representation |
---|---|
bin | 11111010101110000010… |
… | …010101001111111110111 |
3 | 21121212222110001101112121 |
4 | 133111300102221333313 |
5 | 240241200103212403 |
6 | 4325213502500411 |
7 | 311411523443434 |
oct | 37256022517767 |
9 | 7555873041477 |
10 | 2153662554103 |
11 | 7603aa403055 |
12 | 2a9489294707 |
13 | 1281218562b8 |
14 | 76348834b8b |
15 | 3b04d3c83bd |
hex | 1f5704a9ff7 |
2153662554103 has 2 divisors, whose sum is σ = 2153662554104. Its totient is φ = 2153662554102.
The previous prime is 2153662553983. The next prime is 2153662554191. The reversal of 2153662554103 is 3014552663512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2153662554103 - 221 = 2153660456951 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2153662554103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2153662554403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076831277051 + 1076831277052.
It is an arithmetic number, because the mean of its divisors is an integer number (1076831277052).
Almost surely, 22153662554103 is an apocalyptic number.
2153662554103 is a deficient number, since it is larger than the sum of its proper divisors (1).
2153662554103 is an equidigital number, since it uses as much as digits as its factorization.
2153662554103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648000, while the sum is 43.
The spelling of 2153662554103 in words is "two trillion, one hundred fifty-three billion, six hundred sixty-two million, five hundred fifty-four thousand, one hundred three".
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