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2154052113143 = 72229319171499
BaseRepresentation
bin11111010110000111100…
…000101101001011110111
321121220222121002001002012
4133112013200231023313
5240242444320110033
64325320300234435
7311424263601200
oct37260740551367
97556877061065
102154052113143
1176058a297577
122a957783ba1b
131281844803c8
147638447c5a7
153b0726c8248
hex1f58782d2f7

2154052113143 has 12 divisors (see below), whose sum is σ = 2506826997000. Its totient is φ = 1845525083472.

The previous prime is 2154052113139. The next prime is 2154052113163. The reversal of 2154052113143 is 3413112504512.

It is not a de Polignac number, because 2154052113143 - 22 = 2154052113139 is a prime.

It is a super-2 number, since 2×21540521131432 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2154052113163) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9473393 + ... + 9698106.

It is an arithmetic number, because the mean of its divisors is an integer number (208902249750).

Almost surely, 22154052113143 is an apocalyptic number.

2154052113143 is a deficient number, since it is larger than the sum of its proper divisors (352774883857).

2154052113143 is a wasteful number, since it uses less digits than its factorization.

2154052113143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19173806 (or 19173799 counting only the distinct ones).

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 2154052113143 its reverse (3413112504512), we get a palindrome (5567164617655).

The spelling of 2154052113143 in words is "two trillion, one hundred fifty-four billion, fifty-two million, one hundred thirteen thousand, one hundred forty-three".

Divisors: 1 7 49 2293 16051 112357 19171499 134200493 939403451 43960247207 307721730449 2154052113143