Base | Representation |
---|---|
bin | 11111010110010110010… |
… | …110111011111001110111 |
3 | 21121221121221210111001021 |
4 | 133112112112323321313 |
5 | 240244002102211411 |
6 | 4325401115242011 |
7 | 311433410102602 |
oct | 37262626737167 |
9 | 7557557714037 |
10 | 2154301210231 |
11 | 7606a7963935 |
12 | 2a9627149307 |
13 | 1281c3c67b31 |
14 | 763a95a1339 |
15 | 3b0894cea71 |
hex | 1f5965bbe77 |
2154301210231 has 2 divisors, whose sum is σ = 2154301210232. Its totient is φ = 2154301210230.
The previous prime is 2154301210181. The next prime is 2154301210289. The reversal of 2154301210231 is 1320121034512.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2154301210231 - 215 = 2154301177463 is a prime.
It is a super-2 number, since 2×21543012102312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2154301210196 and 2154301210205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2154301210031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1077150605115 + 1077150605116.
It is an arithmetic number, because the mean of its divisors is an integer number (1077150605116).
Almost surely, 22154301210231 is an apocalyptic number.
2154301210231 is a deficient number, since it is larger than the sum of its proper divisors (1).
2154301210231 is an equidigital number, since it uses as much as digits as its factorization.
2154301210231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 2154301210231 its reverse (1320121034512), we get a palindrome (3474422244743).
The spelling of 2154301210231 in words is "two trillion, one hundred fifty-four billion, three hundred one million, two hundred ten thousand, two hundred thirty-one".
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