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21553544332121 is a prime number
BaseRepresentation
bin1001110011010010100110…
…10110101000001101011001
32211022111110120012112122012
410321221103112220031121
510311113124322111441
6113501321144435305
74353122630662664
oct471512326501531
984274416175565
1021553544332121
11695a89696a67a
12250127a478b35
13c0464b858ca9
145472a8c366db
152759ccd3c9eb
hex139a535a8359

21553544332121 has 2 divisors, whose sum is σ = 21553544332122. Its totient is φ = 21553544332120.

The previous prime is 21553544332051. The next prime is 21553544332123. The reversal of 21553544332121 is 12123344535512.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13178678760025 + 8374865572096 = 3630245^2 + 2893936^2 .

It is a cyclic number.

It is not a de Polignac number, because 21553544332121 - 218 = 21553544069977 is a prime.

Together with 21553544332123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (21553544332123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10776772166060 + 10776772166061.

It is an arithmetic number, because the mean of its divisors is an integer number (10776772166061).

Almost surely, 221553544332121 is an apocalyptic number.

It is an amenable number.

21553544332121 is a deficient number, since it is larger than the sum of its proper divisors (1).

21553544332121 is an equidigital number, since it uses as much as digits as its factorization.

21553544332121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 432000, while the sum is 41.

Adding to 21553544332121 its reverse (12123344535512), we get a palindrome (33676888867633).

The spelling of 21553544332121 in words is "twenty-one trillion, five hundred fifty-three billion, five hundred forty-four million, three hundred thirty-two thousand, one hundred twenty-one".