Base | Representation |
---|---|
bin | 11111010111011001111… |
… | …001000111010100000111 |
3 | 21122001112220210112021022 |
4 | 133113121321013110013 |
5 | 240303312131241320 |
6 | 4330105352141355 |
7 | 311503445526242 |
oct | 37273171072407 |
9 | 7561486715238 |
10 | 2155434243335 |
11 | 76112949042a |
12 | 2a98a269785b |
13 | 128344913219 |
14 | 76475c5c259 |
15 | 3b103bdd325 |
hex | 1f5d9e47507 |
2155434243335 has 16 divisors (see below), whose sum is σ = 2587656456000. Its totient is φ = 1723590683136.
The previous prime is 2155434243283. The next prime is 2155434243371. The reversal of 2155434243335 is 5333424345512.
It is a cyclic number.
It is not a de Polignac number, because 2155434243335 - 26 = 2155434243271 is a prime.
It is a super-2 number, since 2×21554342433352 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 183920606 + ... + 183932324.
It is an arithmetic number, because the mean of its divisors is an integer number (161728528500).
Almost surely, 22155434243335 is an apocalyptic number.
2155434243335 is a deficient number, since it is larger than the sum of its proper divisors (432222212665).
2155434243335 is a wasteful number, since it uses less digits than its factorization.
2155434243335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24730.
The product of its digits is 2592000, while the sum is 44.
Adding to 2155434243335 its reverse (5333424345512), we get a palindrome (7488858588847).
The spelling of 2155434243335 in words is "two trillion, one hundred fifty-five billion, four hundred thirty-four million, two hundred forty-three thousand, three hundred thirty-five".
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