Base | Representation |
---|---|
bin | 11111010111011111110… |
… | …110100111101111111011 |
3 | 21122001210212222112210212 |
4 | 133113133312213233323 |
5 | 240304013232044201 |
6 | 4330123323501335 |
7 | 311506101561614 |
oct | 37273766475773 |
9 | 7561725875725 |
10 | 2155534253051 |
11 | 76117a989193 |
12 | 2a991008784b |
13 | 12835c55b27a |
14 | 76485252c0b |
15 | 3b10c895abb |
hex | 1f5dfda7bfb |
2155534253051 has 2 divisors, whose sum is σ = 2155534253052. Its totient is φ = 2155534253050.
The previous prime is 2155534252871. The next prime is 2155534253053. The reversal of 2155534253051 is 1503524355512.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2155534253051 is a prime.
It is a super-2 number, since 2×21555342530512 (a number of 25 digits) contains 22 as substring.
Together with 2155534253053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2155534253053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1077767126525 + 1077767126526.
It is an arithmetic number, because the mean of its divisors is an integer number (1077767126526).
Almost surely, 22155534253051 is an apocalyptic number.
2155534253051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2155534253051 is an equidigital number, since it uses as much as digits as its factorization.
2155534253051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 450000, while the sum is 41.
The spelling of 2155534253051 in words is "two trillion, one hundred fifty-five billion, five hundred thirty-four million, two hundred fifty-three thousand, fifty-one".
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