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2155534253051 is a prime number
BaseRepresentation
bin11111010111011111110…
…110100111101111111011
321122001210212222112210212
4133113133312213233323
5240304013232044201
64330123323501335
7311506101561614
oct37273766475773
97561725875725
102155534253051
1176117a989193
122a991008784b
1312835c55b27a
1476485252c0b
153b10c895abb
hex1f5dfda7bfb

2155534253051 has 2 divisors, whose sum is σ = 2155534253052. Its totient is φ = 2155534253050.

The previous prime is 2155534252871. The next prime is 2155534253053. The reversal of 2155534253051 is 1503524355512.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2155534253051 is a prime.

It is a super-2 number, since 2×21555342530512 (a number of 25 digits) contains 22 as substring.

Together with 2155534253053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2155534253053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1077767126525 + 1077767126526.

It is an arithmetic number, because the mean of its divisors is an integer number (1077767126526).

Almost surely, 22155534253051 is an apocalyptic number.

2155534253051 is a deficient number, since it is larger than the sum of its proper divisors (1).

2155534253051 is an equidigital number, since it uses as much as digits as its factorization.

2155534253051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 450000, while the sum is 41.

The spelling of 2155534253051 in words is "two trillion, one hundred fifty-five billion, five hundred thirty-four million, two hundred fifty-three thousand, fifty-one".