Base | Representation |
---|---|
bin | 1001110011011011001000… |
… | …00110100000000001100111 |
3 | 2211022221021110122222220011 |
4 | 10321231210012200001213 |
5 | 10311202012243044023 |
6 | 113503355211151051 |
7 | 4353344213640223 |
oct | 471554406400147 |
9 | 84287243588804 |
10 | 21558120284263 |
11 | 6961824977202 |
12 | 2502136a45487 |
13 | c04bca8a6594 |
14 | 5475c0873783 |
15 | 275b9993050d |
hex | 139b641a0067 |
21558120284263 has 2 divisors, whose sum is σ = 21558120284264. Its totient is φ = 21558120284262.
The previous prime is 21558120284209. The next prime is 21558120284293. The reversal of 21558120284263 is 36248202185512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21558120284263 - 213 = 21558120276071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21558120284203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10779060142131 + 10779060142132.
It is an arithmetic number, because the mean of its divisors is an integer number (10779060142132).
Almost surely, 221558120284263 is an apocalyptic number.
21558120284263 is a deficient number, since it is larger than the sum of its proper divisors (1).
21558120284263 is an equidigital number, since it uses as much as digits as its factorization.
21558120284263 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1843200, while the sum is 49.
The spelling of 21558120284263 in words is "twenty-one trillion, five hundred fifty-eight billion, one hundred twenty million, two hundred eighty-four thousand, two hundred sixty-three".
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