Base | Representation |
---|---|
bin | 11111011001010110100… |
… | …001110111011110011011 |
3 | 21122020221122111021022221 |
4 | 133121112201313132123 |
5 | 240322102434114042 |
6 | 4331053050524511 |
7 | 311606326320556 |
oct | 37312641673633 |
9 | 7566848437287 |
10 | 2157525301147 |
11 | 762001871087 |
12 | 2aa186a36737 |
13 | 1285b8bbcb38 |
14 | 765d385b69d |
15 | 3b1c758ad67 |
hex | 1f65687779b |
2157525301147 has 4 divisors (see below), whose sum is σ = 2162905663896. Its totient is φ = 2152144938400.
The previous prime is 2157525301121. The next prime is 2157525301177. The reversal of 2157525301147 is 7411035257512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2157525301147 - 219 = 2157524776859 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2157525301177) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2690180773 + ... + 2690181574.
It is an arithmetic number, because the mean of its divisors is an integer number (540726415974).
Almost surely, 22157525301147 is an apocalyptic number.
2157525301147 is a deficient number, since it is larger than the sum of its proper divisors (5380362749).
2157525301147 is an equidigital number, since it uses as much as digits as its factorization.
2157525301147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5380362748.
The product of its (nonzero) digits is 294000, while the sum is 43.
The spelling of 2157525301147 in words is "two trillion, one hundred fifty-seven billion, five hundred twenty-five million, three hundred one thousand, one hundred forty-seven".
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