Base | Representation |
---|---|
bin | 11111011101001100101… |
… | …001001011011101011001 |
3 | 21122122121102010220010221 |
4 | 133131030221023131121 |
5 | 240404032012210040 |
6 | 4333014512040041 |
7 | 312113545226143 |
oct | 37351451133531 |
9 | 7578542126127 |
10 | 2161654413145 |
11 | 763830620037 |
12 | 2aab39833021 |
13 | 128ac64a8a86 |
14 | 768a5dbdc93 |
15 | 3b369d1674a |
hex | 1f74ca4b759 |
2161654413145 has 4 divisors (see below), whose sum is σ = 2593985295780. Its totient is φ = 1729323530512.
The previous prime is 2161654413143. The next prime is 2161654413199. The reversal of 2161654413145 is 5413144561612.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 361600174224 + 1800054238921 = 601332^2 + 1341661^2 .
It is a cyclic number.
It is not a de Polignac number, because 2161654413145 - 21 = 2161654413143 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2161654413143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216165441310 + ... + 216165441319.
It is an arithmetic number, because the mean of its divisors is an integer number (648496323945).
Almost surely, 22161654413145 is an apocalyptic number.
It is an amenable number.
2161654413145 is a deficient number, since it is larger than the sum of its proper divisors (432330882635).
2161654413145 is an equidigital number, since it uses as much as digits as its factorization.
2161654413145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 432330882634.
The product of its digits is 345600, while the sum is 43.
Adding to 2161654413145 its reverse (5413144561612), we get a palindrome (7574798974757).
The spelling of 2161654413145 in words is "two trillion, one hundred sixty-one billion, six hundred fifty-four million, four hundred thirteen thousand, one hundred forty-five".
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