Base | Representation |
---|---|
bin | 11111011110111010101… |
… | …010000110110100100111 |
3 | 21122211101001020001012020 |
4 | 133132322222012310213 |
5 | 240421322014300210 |
6 | 4333522004354223 |
7 | 312210356564256 |
oct | 37367252066447 |
9 | 7584331201166 |
10 | 2163500150055 |
11 | 764598483542 |
12 | 2ab3739a5973 |
13 | 12902b9c09aa |
14 | 769dd1a079d |
15 | 3b426da6770 |
hex | 1f7baa86d27 |
2163500150055 has 32 divisors (see below), whose sum is σ = 3470691248640. Its totient is φ = 1150837733760.
The previous prime is 2163500149933. The next prime is 2163500150057. The reversal of 2163500150055 is 5500510053612.
It is not a de Polignac number, because 2163500150055 - 218 = 2163499887911 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2163500149998 and 2163500150025.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2163500150057) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27747054 + ... + 27824916.
It is an arithmetic number, because the mean of its divisors is an integer number (108459101520).
Almost surely, 22163500150055 is an apocalyptic number.
2163500150055 is a deficient number, since it is larger than the sum of its proper divisors (1307191098585).
2163500150055 is a wasteful number, since it uses less digits than its factorization.
2163500150055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 82711.
The product of its (nonzero) digits is 22500, while the sum is 33.
The spelling of 2163500150055 in words is "two trillion, one hundred sixty-three billion, five hundred million, one hundred fifty thousand, fifty-five".
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