Base | Representation |
---|---|
bin | 11111011111011111010… |
… | …000111110111011101100 |
3 | 21122212221211220011112011 |
4 | 133133133100332323230 |
5 | 240424101231234012 |
6 | 4334102544251004 |
7 | 312231525134431 |
oct | 37373720767354 |
9 | 7585854804464 |
10 | 2164114321132 |
11 | 764883130345 |
12 | 2ab505610a64 |
13 | 1290c900b82a |
14 | 76a5a995b88 |
15 | 3b460c731a7 |
hex | 1f7df43eeec |
2164114321132 has 24 divisors (see below), whose sum is σ = 3933334379520. Its totient is φ = 1041084922320.
The previous prime is 2164114321091. The next prime is 2164114321181. The reversal of 2164114321132 is 2311234114612.
It is a happy number.
It is a super-2 number, since 2×21641143211322 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2164114321094 and 2164114321103.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 97541844 + ... + 97564027.
It is an arithmetic number, because the mean of its divisors is an integer number (163888932480).
Almost surely, 22164114321132 is an apocalyptic number.
It is an amenable number.
2164114321132 is a deficient number, since it is larger than the sum of its proper divisors (1769220058388).
2164114321132 is a wasteful number, since it uses less digits than its factorization.
2164114321132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 195105981 (or 195105979 counting only the distinct ones).
The product of its digits is 6912, while the sum is 31.
Adding to 2164114321132 its reverse (2311234114612), we get a palindrome (4475348435744).
The spelling of 2164114321132 in words is "two trillion, one hundred sixty-four billion, one hundred fourteen million, three hundred twenty-one thousand, one hundred thirty-two".
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