Base | Representation |
---|---|
bin | 110001001101011000000001… |
… | …001110100111000011101011 |
3 | 1001101021212200102211021022120 |
4 | 301031120001032213003223 |
5 | 211331340132144341101 |
6 | 2044143314154322323 |
7 | 63405035111443344 |
oct | 6115300116470353 |
9 | 1041255612737276 |
10 | 216423422652651 |
11 | 62a60726a38795 |
12 | 203343864293a3 |
13 | 939b8448b78b6 |
14 | 3b62d417b30cb |
15 | 1a04a0ad0db36 |
hex | c4d6013a70eb |
216423422652651 has 64 divisors (see below), whose sum is σ = 317944928125440. Its totient is φ = 130420093040640.
The previous prime is 216423422652571. The next prime is 216423422652691. The reversal of 216423422652651 is 156256224324612.
It is not a de Polignac number, because 216423422652651 - 29 = 216423422652139 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a junction number, because it is equal to n+sod(n) for n = 216423422652594 and 216423422652603.
It is not an unprimeable number, because it can be changed into a prime (216423422652691) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 20028936 + ... + 28879146.
It is an arithmetic number, because the mean of its divisors is an integer number (4967889501960).
Almost surely, 2216423422652651 is an apocalyptic number.
216423422652651 is a deficient number, since it is larger than the sum of its proper divisors (101521505472789).
216423422652651 is a wasteful number, since it uses less digits than its factorization.
216423422652651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8850476.
The product of its digits is 8294400, while the sum is 51.
The spelling of 216423422652651 in words is "two hundred sixteen trillion, four hundred twenty-three billion, four hundred twenty-two million, six hundred fifty-two thousand, six hundred fifty-one".
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