Search a number
-
+
216754172114437 is a prime number
BaseRepresentation
bin110001010010001100000011…
…011011101011011000000101
31001102110111101221021210201201
4301102030003123223120011
5211402300021030130222
62044555254135222501
763440654306462446
oct6122140333533005
91042414357253651
10216754172114437
1163078a23430821
12203884b1817a31
1393c3aa51480b9
143b74d5a6d12cd
151a0d417cd9427
hexc523036eb605

216754172114437 has 2 divisors, whose sum is σ = 216754172114438. Its totient is φ = 216754172114436.

The previous prime is 216754172114401. The next prime is 216754172114461. The reversal of 216754172114437 is 734411271457612.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 216745263397441 + 8908716996 = 14722271^2 + 94386^2 .

It is a cyclic number.

It is not a de Polignac number, because 216754172114437 - 215 = 216754172081669 is a prime.

It is a super-2 number, since 2×2167541721144372 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (216754172114737) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 108377086057218 + 108377086057219.

It is an arithmetic number, because the mean of its divisors is an integer number (108377086057219).

Almost surely, 2216754172114437 is an apocalyptic number.

It is an amenable number.

216754172114437 is a deficient number, since it is larger than the sum of its proper divisors (1).

216754172114437 is an equidigital number, since it uses as much as digits as its factorization.

216754172114437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7902720, while the sum is 55.

The spelling of 216754172114437 in words is "two hundred sixteen trillion, seven hundred fifty-four billion, one hundred seventy-two million, one hundred fourteen thousand, four hundred thirty-seven".