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21707995345 = 54341599069
BaseRepresentation
bin10100001101111001…
…011011100011010001
32002000212102102101121
4110031321123203101
5323424221322340
613550021402241
71365641626111
oct241571334321
962025372347
1021707995345
11922a663223
124259b69381
13207c4c347a
14109d08d041
15870b9d94a
hex50de5b8d1

21707995345 has 4 divisors (see below), whose sum is σ = 26049594420. Its totient is φ = 17366396272.

The previous prime is 21707995339. The next prime is 21707995363. The reversal of 21707995345 is 54359970712.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3731621569 + 17976373776 = 61087^2 + 134076^2 .

It is a cyclic number.

It is not a de Polignac number, because 21707995345 - 25 = 21707995313 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21707995292 and 21707995301.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2170799530 + ... + 2170799539.

It is an arithmetic number, because the mean of its divisors is an integer number (6512398605).

Almost surely, 221707995345 is an apocalyptic number.

It is an amenable number.

21707995345 is a deficient number, since it is larger than the sum of its proper divisors (4341599075).

21707995345 is an equidigital number, since it uses as much as digits as its factorization.

21707995345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4341599074.

The product of its (nonzero) digits is 2381400, while the sum is 52.

The spelling of 21707995345 in words is "twenty-one billion, seven hundred seven million, nine hundred ninety-five thousand, three hundred forty-five".

Divisors: 1 5 4341599069 21707995345