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21790714313437 is a prime number
BaseRepresentation
bin1001111010001100010111…
…10010010011101011011101
32212011011122100100220211021
410331012023302103223131
510324004340331012222
6114202303240324141
74406220133365316
oct475061362235335
985134570326737
1021790714313437
116a414321689a3
12253b22a173651
13c20b1781cb44
145549676c960d
1527bc5e5ceac7
hex13d18bc93add

21790714313437 has 2 divisors, whose sum is σ = 21790714313438. Its totient is φ = 21790714313436.

The previous prime is 21790714313393. The next prime is 21790714313453. The reversal of 21790714313437 is 73431341709712.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11171497379641 + 10619216933796 = 3342379^2 + 3258714^2 .

It is a cyclic number.

It is not a de Polignac number, because 21790714313437 - 243 = 12994621291229 is a prime.

It is a super-3 number, since 3×217907143134373 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21790714314437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10895357156718 + 10895357156719.

It is an arithmetic number, because the mean of its divisors is an integer number (10895357156719).

Almost surely, 221790714313437 is an apocalyptic number.

It is an amenable number.

21790714313437 is a deficient number, since it is larger than the sum of its proper divisors (1).

21790714313437 is an equidigital number, since it uses as much as digits as its factorization.

21790714313437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2667168, while the sum is 52.

It can be divided in two parts, 217907 and 14313437, that added together give a square (14531344 = 38122).

The spelling of 21790714313437 in words is "twenty-one trillion, seven hundred ninety billion, seven hundred fourteen million, three hundred thirteen thousand, four hundred thirty-seven".