Base | Representation |
---|---|
bin | 10100010101010100… |
… | …011000010011001001 |
3 | 2002100112200221020212 |
4 | 110111110120103021 |
5 | 324203110003200 |
6 | 14010230130505 |
7 | 1402013122511 |
oct | 242524302311 |
9 | 62315627225 |
10 | 21832500425 |
11 | 929397178a |
12 | 42937b0a35 |
13 | 209c236b08 |
14 | 10b181c841 |
15 | 87ba94035 |
hex | 5155184c9 |
21832500425 has 12 divisors (see below), whose sum is σ = 27074957196. Its totient is φ = 17464286400.
The previous prime is 21832500401. The next prime is 21832500457. The reversal of 21832500425 is 52400523812.
It can be written as a sum of positive squares in 6 ways, for example, as 5793797689 + 16038702736 = 76117^2 + 126644^2 .
It is not a de Polignac number, because 21832500425 - 210 = 21832499401 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 21832500391 and 21832500400.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 258587 + ... + 332463.
It is an arithmetic number, because the mean of its divisors is an integer number (2256246433).
Almost surely, 221832500425 is an apocalyptic number.
21832500425 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
21832500425 is a deficient number, since it is larger than the sum of its proper divisors (5242456771).
21832500425 is a wasteful number, since it uses less digits than its factorization.
21832500425 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85708 (or 85703 counting only the distinct ones).
The product of its (nonzero) digits is 19200, while the sum is 32.
The spelling of 21832500425 in words is "twenty-one billion, eight hundred thirty-two million, five hundred thousand, four hundred twenty-five".
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