Base | Representation |
---|---|
bin | 1000001100100001… |
… | …1000000101101001 |
3 | 12200022201010220002 |
4 | 2003020120011221 |
5 | 14001200323423 |
6 | 1002145512345 |
7 | 105342533366 |
oct | 20310300551 |
9 | 5608633802 |
10 | 2200011113 |
11 | a29937a03 |
12 | 5149426b5 |
13 | 290a36731 |
14 | 16c28146d |
15 | cd220228 |
hex | 83218169 |
2200011113 has 2 divisors, whose sum is σ = 2200011114. Its totient is φ = 2200011112.
The previous prime is 2200011091. The next prime is 2200011127. The reversal of 2200011113 is 3111100022.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2065520704 + 134490409 = 45448^2 + 11597^2 .
It is a cyclic number.
It is not a de Polignac number, because 2200011113 - 210 = 2200010089 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2200011094 and 2200011103.
It is not a weakly prime, because it can be changed into another prime (2200011413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1100005556 + 1100005557.
It is an arithmetic number, because the mean of its divisors is an integer number (1100005557).
Almost surely, 22200011113 is an apocalyptic number.
It is an amenable number.
2200011113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2200011113 is an equidigital number, since it uses as much as digits as its factorization.
2200011113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 11.
The square root of 2200011113 is about 46904.2760630627. The cubic root of 2200011113 is about 1300.5936367678.
Adding to 2200011113 its reverse (3111100022), we get a palindrome (5311111135).
The spelling of 2200011113 in words is "two billion, two hundred million, eleven thousand, one hundred thirteen".
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