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2200112313122 = 21100056156561
BaseRepresentation
bin100000000001000000111…
…010011011001100100010
321210022212121110122002202
4200001000322123030202
5242021312223004442
64402415002213202
7314644556046413
oct40010072331442
97708777418082
102200112313122
11779076053549
122b64911b4202
1312c614c186c9
14786b384980a
153c36b239c32
hex20040e9b322

2200112313122 has 4 divisors (see below), whose sum is σ = 3300168469686. Its totient is φ = 1100056156560.

The previous prime is 2200112313121. The next prime is 2200112313143. The reversal of 2200112313122 is 2213132110022.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1592368895881 + 607743417241 = 1261891^2 + 779579^2 .

It is a junction number, because it is equal to n+sod(n) for n = 2200112313094 and 2200112313103.

It is not an unprimeable number, because it can be changed into a prime (2200112313121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550028078279 + ... + 550028078282.

Almost surely, 22200112313122 is an apocalyptic number.

2200112313122 is a deficient number, since it is larger than the sum of its proper divisors (1100056156564).

2200112313122 is a wasteful number, since it uses less digits than its factorization.

2200112313122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1100056156563.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 2200112313122 its reverse (2213132110022), we get a palindrome (4413244423144).

The spelling of 2200112313122 in words is "two trillion, two hundred billion, one hundred twelve million, three hundred thirteen thousand, one hundred twenty-two".

Divisors: 1 2 1100056156561 2200112313122