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22002020113 = 87472515379
BaseRepresentation
bin10100011111011011…
…000010111100010001
32002210100200102112211
4110133123002330101
5330030004120423
614035123352121
71406142041143
oct243733027421
962710612484
1022002020113
1193706263a7
124320522641
1320c83ab618
1410ca148c93
1588b8cc10d
hex51f6c2f11

22002020113 has 4 divisors (see below), whose sum is σ = 22004544240. Its totient is φ = 21999495988.

The previous prime is 22002020093. The next prime is 22002020137. The reversal of 22002020113 is 31102020022.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 22002020113 - 25 = 22002020081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 22002020093 and 22002020102.

It is not an unprimeable number, because it can be changed into a prime (22002020153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1248943 + ... + 1266436.

It is an arithmetic number, because the mean of its divisors is an integer number (5501136060).

Almost surely, 222002020113 is an apocalyptic number.

It is an amenable number.

22002020113 is a deficient number, since it is larger than the sum of its proper divisors (2524127).

22002020113 is an equidigital number, since it uses as much as digits as its factorization.

22002020113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2524126.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 22002020113 its reverse (31102020022), we get a palindrome (53104040135).

Subtracting 22002020113 from its reverse (31102020022), we obtain a palindrome (9099999909).

The spelling of 22002020113 in words is "twenty-two billion, two million, twenty thousand, one hundred thirteen".

Divisors: 1 8747 2515379 22002020113