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22002113113 = 54521403553
BaseRepresentation
bin10100011111011011…
…011001101001011001
32002210100212011010021
4110133123121221121
5330030020104423
614035125350441
71406142606241
oct243733315131
962710764107
1022002113113
11937068a262
124320568421
1320c8411a56
1410ca170b21
1588b8e995d
hex51f6d9a59

22002113113 has 4 divisors (see below), whose sum is σ = 22002571188. Its totient is φ = 22001655040.

The previous prime is 22002113101. The next prime is 22002113117. The reversal of 22002113113 is 31131120022.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4533732889 + 17468380224 = 67333^2 + 132168^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-22002113113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (22002113117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 147256 + ... + 256297.

It is an arithmetic number, because the mean of its divisors is an integer number (5500642797).

Almost surely, 222002113113 is an apocalyptic number.

It is an amenable number.

22002113113 is a deficient number, since it is larger than the sum of its proper divisors (458075).

22002113113 is an equidigital number, since it uses as much as digits as its factorization.

22002113113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 458074.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 22002113113 its reverse (31131120022), we get a palindrome (53133233135).

The spelling of 22002113113 in words is "twenty-two billion, two million, one hundred thirteen thousand, one hundred thirteen".

Divisors: 1 54521 403553 22002113113