Base | Representation |
---|---|
bin | 110010000011000010011100… |
… | …100101101011110111101001 |
3 | 1001212100102020210020210010221 |
4 | 302003002130211223313221 |
5 | 212322300023421010441 |
6 | 2100045352024210041 |
7 | 64235334345235120 |
oct | 6203023445536751 |
9 | 1055312223223127 |
10 | 220111111110121 |
11 | 64152663a33a20 |
12 | 2082b011909921 |
13 | 95a850901040a |
14 | 3c4d612856ab7 |
15 | 1a6a8dd84a8d1 |
hex | c8309c96bde9 |
220111111110121 has 8 divisors (see below), whose sum is σ = 274424242423104. Its totient is φ = 171515151514320.
The previous prime is 220111111110073. The next prime is 220111111110167. The reversal of 220111111110121 is 121011111111022.
220111111110121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 220111111110121 - 213 = 220111111101929 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 220111111110095 and 220111111110104.
It is not an unprimeable number, because it can be changed into a prime (220111111110721) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1429292929210 + ... + 1429292929363.
It is an arithmetic number, because the mean of its divisors is an integer number (34303030302888).
Almost surely, 2220111111110121 is an apocalyptic number.
It is an amenable number.
220111111110121 is a deficient number, since it is larger than the sum of its proper divisors (54313131312983).
220111111110121 is a wasteful number, since it uses less digits than its factorization.
220111111110121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2858585858591.
The product of its (nonzero) digits is 8, while the sum is 16.
Adding to 220111111110121 its reverse (121011111111022), we get a palindrome (341122222221143).
Subtracting from 220111111110121 its reverse (121011111111022), we obtain a palindrome (99099999999099).
The spelling of 220111111110121 in words is "two hundred twenty trillion, one hundred eleven billion, one hundred eleven million, one hundred ten thousand, one hundred twenty-one".
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