Base | Representation |
---|---|
bin | 100000000001111100011… |
… | …110010100010100111001 |
3 | 21210102110020202112200211 |
4 | 200001330132110110321 |
5 | 242030334030443123 |
6 | 4403102100031121 |
7 | 315011411466013 |
oct | 40017436242471 |
9 | 7712406675624 |
10 | 2201111577913 |
11 | 779539114a16 |
12 | 2b670b9924a1 |
13 | 12c743c59051 |
14 | 7876a4451b3 |
15 | 3c3c8d2340d |
hex | 2007c794539 |
2201111577913 has 2 divisors, whose sum is σ = 2201111577914. Its totient is φ = 2201111577912.
The previous prime is 2201111577893. The next prime is 2201111577971. The reversal of 2201111577913 is 3197751111022.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1769879015424 + 431232562489 = 1330368^2 + 656683^2 .
It is a cyclic number.
It is not a de Polignac number, because 2201111577913 - 213 = 2201111569721 is a prime.
It is not a weakly prime, because it can be changed into another prime (2201111577983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1100555788956 + 1100555788957.
It is an arithmetic number, because the mean of its divisors is an integer number (1100555788957).
Almost surely, 22201111577913 is an apocalyptic number.
It is an amenable number.
2201111577913 is a deficient number, since it is larger than the sum of its proper divisors (1).
2201111577913 is an equidigital number, since it uses as much as digits as its factorization.
2201111577913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26460, while the sum is 40.
Adding to 2201111577913 its reverse (3197751111022), we get a palindrome (5398862688935).
The spelling of 2201111577913 in words is "two trillion, two hundred one billion, one hundred eleven million, five hundred seventy-seven thousand, nine hundred thirteen".
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