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22012044433 = 35961314887
BaseRepresentation
bin10100100000000001…
…010010010010010001
32002211001112201022221
4110200001102102101
5330040040410213
614040122301041
71406323201441
oct244001222221
962731481287
1022012044433
119376252865
124323957781
1320ca4ab282
1410cb5d8121
1588c70c38d
hex520052491

22012044433 has 4 divisors (see below), whose sum is σ = 22073359680. Its totient is φ = 21950729188.

The previous prime is 22012044413. The next prime is 22012044449. The reversal of 22012044433 is 33444021022.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33444021022 = 216722010511.

It is a cyclic number.

It is not a de Polignac number, because 22012044433 - 229 = 21475173521 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 22012044398 and 22012044407.

It is not an unprimeable number, because it can be changed into a prime (22012044413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30657085 + ... + 30657802.

It is an arithmetic number, because the mean of its divisors is an integer number (5518339920).

Almost surely, 222012044433 is an apocalyptic number.

It is an amenable number.

22012044433 is a deficient number, since it is larger than the sum of its proper divisors (61315247).

22012044433 is an equidigital number, since it uses as much as digits as its factorization.

22012044433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61315246.

The product of its (nonzero) digits is 4608, while the sum is 25.

Adding to 22012044433 its reverse (33444021022), we get a palindrome (55456065455).

The spelling of 22012044433 in words is "twenty-two billion, twelve million, forty-four thousand, four hundred thirty-three".

Divisors: 1 359 61314887 22012044433