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220121112202102 = 2110060556101051
BaseRepresentation
bin110010000011001011110000…
…101100110100101101110110
31001212101101001210001220012001
4302003023300230310231312
5212322431014210431402
62100054124250245514
764236140235145516
oct6203136054645566
91055341053056161
10220121112202102
11641569263243a1
1220830b4312689a
1395a9440cc0917
143c4dcc0bc1846
151a6acc6872187
hexc832f0b34b76

220121112202102 has 4 divisors (see below), whose sum is σ = 330181668303156. Its totient is φ = 110060556101050.

The previous prime is 220121112202097. The next prime is 220121112202133. The reversal of 220121112202102 is 201202211121022.

220121112202102 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 220121112202102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55030278050524 + ... + 55030278050527.

It is an arithmetic number, because the mean of its divisors is an integer number (82545417075789).

Almost surely, 2220121112202102 is an apocalyptic number.

220121112202102 is a deficient number, since it is larger than the sum of its proper divisors (110060556101054).

220121112202102 is a wasteful number, since it uses less digits than its factorization.

220121112202102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110060556101053.

The product of its (nonzero) digits is 128, while the sum is 19.

Adding to 220121112202102 its reverse (201202211121022), we get a palindrome (421323323323124).

The spelling of 220121112202102 in words is "two hundred twenty trillion, one hundred twenty-one billion, one hundred twelve million, two hundred two thousand, one hundred two".

Divisors: 1 2 110060556101051 220121112202102