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22013003121 = 37337667707
BaseRepresentation
bin10100100000000100…
…111100010101110001
32002211010100102101220
4110200010330111301
5330040312044441
614040155015253
71406334303444
oct244004742561
962733312356
1022013003121
11937684806a
12432413a529
1320ca755745
1410cb7a765b
1588c84b466
hex52013c571

22013003121 has 4 divisors (see below), whose sum is σ = 29350670832. Its totient is φ = 14675335412.

The previous prime is 22013003069. The next prime is 22013003141. The reversal of 22013003121 is 12130031022.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-22013003121 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 22013003121.

It is not an unprimeable number, because it can be changed into a prime (22013003141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3668833851 + ... + 3668833856.

It is an arithmetic number, because the mean of its divisors is an integer number (7337667708).

Almost surely, 222013003121 is an apocalyptic number.

It is an amenable number.

22013003121 is a deficient number, since it is larger than the sum of its proper divisors (7337667711).

22013003121 is an equidigital number, since it uses as much as digits as its factorization.

22013003121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7337667710.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 22013003121 its reverse (12130031022), we get a palindrome (34143034143).

The spelling of 22013003121 in words is "twenty-two billion, thirteen million, three thousand, one hundred twenty-one".

Divisors: 1 3 7337667707 22013003121