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220131130310249 is a prime number
BaseRepresentation
bin110010000011010101000101…
…110100110111111001101001
31001212102022220221220112000112
4302003111011310313321221
5212323112023324411444
62100102502321144105
764236643422520064
oct6203250564677151
91055368827815015
10220131130310249
11641600a7287314
1220832a7a18b035
1395aa37967b372
143c505914d98db
151a6b1b110a69e
hexc83545d37e69

220131130310249 has 2 divisors, whose sum is σ = 220131130310250. Its totient is φ = 220131130310248.

The previous prime is 220131130310237. The next prime is 220131130310251. The reversal of 220131130310249 is 942013031131022.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 219528227755225 + 602902555024 = 14816485^2 + 776468^2 .

It is a cyclic number.

It is not a de Polignac number, because 220131130310249 - 224 = 220131113533033 is a prime.

It is a Sophie Germain prime.

Together with 220131130310251, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (220131130310209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110065565155124 + 110065565155125.

It is an arithmetic number, because the mean of its divisors is an integer number (110065565155125).

Almost surely, 2220131130310249 is an apocalyptic number.

It is an amenable number.

220131130310249 is a deficient number, since it is larger than the sum of its proper divisors (1).

220131130310249 is an equidigital number, since it uses as much as digits as its factorization.

220131130310249 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 32.

The spelling of 220131130310249 in words is "two hundred twenty trillion, one hundred thirty-one billion, one hundred thirty million, three hundred ten thousand, two hundred forty-nine".