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2204134112113 is a prime number
BaseRepresentation
bin100000000100110000101…
…000010111101101110001
321210201020220012012010221
4200010300220113231301
5242103031313041423
64404322031253041
7315146332554043
oct40046050275561
97721226165127
102204134112113
1177a84a27666a
122b721407a181
1312cb0620031b
1478975a35a93
153c504368e5d
hex20130a17b71

2204134112113 has 2 divisors, whose sum is σ = 2204134112114. Its totient is φ = 2204134112112.

The previous prime is 2204134112101. The next prime is 2204134112123. The reversal of 2204134112113 is 3112114314022.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1561480166464 + 642653945649 = 1249592^2 + 801657^2 .

It is a cyclic number.

It is not a de Polignac number, because 2204134112113 - 217 = 2204133981041 is a prime.

It is a super-3 number, since 3×22041341121133 (a number of 38 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (2204134112123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1102067056056 + 1102067056057.

It is an arithmetic number, because the mean of its divisors is an integer number (1102067056057).

Almost surely, 22204134112113 is an apocalyptic number.

It is an amenable number.

2204134112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2204134112113 is an equidigital number, since it uses as much as digits as its factorization.

2204134112113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 2204134112113 its reverse (3112114314022), we get a palindrome (5316248426135).

The spelling of 2204134112113 in words is "two trillion, two hundred four billion, one hundred thirty-four million, one hundred twelve thousand, one hundred thirteen".