Base | Representation |
---|---|
bin | 100000001010010100010… |
… | …010101101000001101011 |
3 | 21211021122202011122200221 |
4 | 200022110102231001223 |
5 | 242202241341334011 |
6 | 4411150105110511 |
7 | 315450236365561 |
oct | 40122422550153 |
9 | 7737582148627 |
10 | 2210101121131 |
11 | 782331513882 |
12 | 2b83ba488437 |
13 | 1305474b78a7 |
14 | 78d802d7a31 |
15 | 3c753136971 |
hex | 202944ad06b |
2210101121131 has 2 divisors, whose sum is σ = 2210101121132. Its totient is φ = 2210101121130.
The previous prime is 2210101121009. The next prime is 2210101121153. The reversal of 2210101121131 is 1311211010122.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2210101121131 - 213 = 2210101112939 is a prime.
It is a super-2 number, since 2×22101011211312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2210101121731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1105050560565 + 1105050560566.
It is an arithmetic number, because the mean of its divisors is an integer number (1105050560566).
Almost surely, 22210101121131 is an apocalyptic number.
2210101121131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2210101121131 is an equidigital number, since it uses as much as digits as its factorization.
2210101121131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 2210101121131 its reverse (1311211010122), we get a palindrome (3521312131253).
The spelling of 2210101121131 in words is "two trillion, two hundred ten billion, one hundred one million, one hundred twenty-one thousand, one hundred thirty-one".
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