Base | Representation |
---|---|
bin | 100000001010010100010… |
… | …011000011001111010001 |
3 | 21211021122202100021111122 |
4 | 200022110103003033101 |
5 | 242202241402241423 |
6 | 4411150111052025 |
7 | 315450240225044 |
oct | 40122423031721 |
9 | 7737582307448 |
10 | 2210101212113 |
11 | 782331576173 |
12 | 2b83ba511015 |
13 | 13054751a122 |
14 | 78d8031cc5b |
15 | 3c7531538c8 |
hex | 202944c33d1 |
2210101212113 has 16 divisors (see below), whose sum is σ = 2331242639040. Its totient is φ = 2089444896000.
The previous prime is 2210101212107. The next prime is 2210101212157. The reversal of 2210101212113 is 3112121010122.
It is a happy number.
It is not a de Polignac number, because 2210101212113 - 210 = 2210101211089 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 2210101212091 and 2210101212100.
It is not an unprimeable number, because it can be changed into a prime (2210101212103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26698838 + ... + 26781488.
It is an arithmetic number, because the mean of its divisors is an integer number (145702664940).
Almost surely, 22210101212113 is an apocalyptic number.
It is an amenable number.
2210101212113 is a deficient number, since it is larger than the sum of its proper divisors (121141426927).
2210101212113 is a wasteful number, since it uses less digits than its factorization.
2210101212113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85568.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 2210101212113 its reverse (3112121010122), we get a palindrome (5322222222235).
The spelling of 2210101212113 in words is "two trillion, two hundred ten billion, one hundred one million, two hundred twelve thousand, one hundred thirteen".
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