Base | Representation |
---|---|
bin | 1010000011001110100100… |
… | …00101001110011100001011 |
3 | 2220020211212211201212110211 |
4 | 11001213102011032130023 |
5 | 10344101104104320042 |
6 | 115001041454221551 |
7 | 4440516431420452 |
oct | 501472205163413 |
9 | 86224784655424 |
10 | 22101131323147 |
11 | 7051045502828 |
12 | 258b4201b48b7 |
13 | c44187854806 |
14 | 5659b4101b99 |
15 | 284d7b570017 |
hex | 1419d214e70b |
22101131323147 has 2 divisors, whose sum is σ = 22101131323148. Its totient is φ = 22101131323146.
The previous prime is 22101131323109. The next prime is 22101131323151. The reversal of 22101131323147 is 74132313110122.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-22101131323147 is a prime.
It is not a weakly prime, because it can be changed into another prime (22101131323547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11050565661573 + 11050565661574.
It is an arithmetic number, because the mean of its divisors is an integer number (11050565661574).
Almost surely, 222101131323147 is an apocalyptic number.
22101131323147 is a deficient number, since it is larger than the sum of its proper divisors (1).
22101131323147 is an equidigital number, since it uses as much as digits as its factorization.
22101131323147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 22101131323147 its reverse (74132313110122), we get a palindrome (96233444433269).
The spelling of 22101131323147 in words is "twenty-two trillion, one hundred one billion, one hundred thirty-one million, three hundred twenty-three thousand, one hundred forty-seven".
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