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221113131121 is a prime number
BaseRepresentation
bin1100110111101101011…
…1101010000001110001
3210010201202100212120201
43031323113222001301
512110314430143441
6245324501435201
721655250414101
oct3157327520161
9703652325521
10221113131121
11858566640a3
1236a2a40bb01
1317b0a4c457c
14a9b8163201
155b41cbbc31
hex337b5ea071

221113131121 has 2 divisors, whose sum is σ = 221113131122. Its totient is φ = 221113131120.

The previous prime is 221113131037. The next prime is 221113131193. The reversal of 221113131121 is 121131311122.

It is a m-pointer prime, because the next prime (221113131193) can be obtained adding 221113131121 to its product of digits (72).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 214234751025 + 6878380096 = 462855^2 + 82936^2 .

It is a cyclic number.

It is not a de Polignac number, because 221113131121 - 237 = 83674177649 is a prime.

It is not a weakly prime, because it can be changed into another prime (221113131221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110556565560 + 110556565561.

It is an arithmetic number, because the mean of its divisors is an integer number (110556565561).

Almost surely, 2221113131121 is an apocalyptic number.

It is an amenable number.

221113131121 is a deficient number, since it is larger than the sum of its proper divisors (1).

221113131121 is an equidigital number, since it uses as much as digits as its factorization.

221113131121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 72, while the sum is 19.

Adding to 221113131121 its reverse (121131311122), we get a palindrome (342244442243).

The spelling of 221113131121 in words is "two hundred twenty-one billion, one hundred thirteen million, one hundred thirty-one thousand, one hundred twenty-one".