Base | Representation |
---|---|
bin | 100000001011011001011… |
… | …100110111011100011011 |
3 | 21211101122121110121010022 |
4 | 200023121130313130123 |
5 | 242212130410210042 |
6 | 4411501154141055 |
7 | 315521055613253 |
oct | 40133134673433 |
9 | 7741577417108 |
10 | 2211261413147 |
11 | 7828774693a6 |
12 | 2b8682b8178b |
13 | 1306a09b8407 |
14 | 7905044c963 |
15 | 3c7bee2bcd2 |
hex | 202d973771b |
2211261413147 has 2 divisors, whose sum is σ = 2211261413148. Its totient is φ = 2211261413146.
The previous prime is 2211261413129. The next prime is 2211261413183. The reversal of 2211261413147 is 7413141621122.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2211261413147 - 26 = 2211261413083 is a prime.
It is not a weakly prime, because it can be changed into another prime (2211261413117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1105630706573 + 1105630706574.
It is an arithmetic number, because the mean of its divisors is an integer number (1105630706574).
Almost surely, 22211261413147 is an apocalyptic number.
2211261413147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2211261413147 is an equidigital number, since it uses as much as digits as its factorization.
2211261413147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 16128, while the sum is 35.
The spelling of 2211261413147 in words is "two trillion, two hundred eleven billion, two hundred sixty-one million, four hundred thirteen thousand, one hundred forty-seven".
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