Base | Representation |
---|---|
bin | 100000001011011100010… |
… | …111011011100111111111 |
3 | 21211101210000111022212221 |
4 | 200023130113123213333 |
5 | 242212230420221002 |
6 | 4411510102310211 |
7 | 315522221406226 |
oct | 40133427334777 |
9 | 7741700438787 |
10 | 2211310320127 |
11 | 7828a2032997 |
12 | 2b8697428367 |
13 | 1306aab8015c |
14 | 79056b3dcbd |
15 | 3c7c438cc37 |
hex | 202dc5db9ff |
2211310320127 has 2 divisors, whose sum is σ = 2211310320128. Its totient is φ = 2211310320126.
The previous prime is 2211310320077. The next prime is 2211310320133. The reversal of 2211310320127 is 7210230131122.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2211310320127 is a prime.
It is a super-2 number, since 2×22113103201272 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2211310330127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1105655160063 + 1105655160064.
It is an arithmetic number, because the mean of its divisors is an integer number (1105655160064).
Almost surely, 22211310320127 is an apocalyptic number.
2211310320127 is a deficient number, since it is larger than the sum of its proper divisors (1).
2211310320127 is an equidigital number, since it uses as much as digits as its factorization.
2211310320127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 2211310320127 its reverse (7210230131122), we get a palindrome (9421540451249).
The spelling of 2211310320127 in words is "two trillion, two hundred eleven billion, three hundred ten million, three hundred twenty thousand, one hundred twenty-seven".
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