Base | Representation |
---|---|
bin | 110010010001111000011000… |
… | …110110110000111100101011 |
3 | 1001222221221000210100011202001 |
4 | 302101320120312300330223 |
5 | 212441002444410230212 |
6 | 2102150120522551431 |
7 | 64402123611112342 |
oct | 6221703066607453 |
9 | 1058857023304661 |
10 | 221131103211307 |
11 | 645061a0983393 |
12 | 20974833068577 |
13 | 965075c149513 |
14 | 3c86b340cab59 |
15 | 1a871da2bc657 |
hex | c91e18db0f2b |
221131103211307 has 2 divisors, whose sum is σ = 221131103211308. Its totient is φ = 221131103211306.
The previous prime is 221131103211301. The next prime is 221131103211349. The reversal of 221131103211307 is 703112301131122.
It is a happy number.
221131103211307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 221131103211307 - 235 = 221096743472939 is a prime.
It is not a weakly prime, because it can be changed into another prime (221131103211301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110565551605653 + 110565551605654.
It is an arithmetic number, because the mean of its divisors is an integer number (110565551605654).
Almost surely, 2221131103211307 is an apocalyptic number.
221131103211307 is a deficient number, since it is larger than the sum of its proper divisors (1).
221131103211307 is an equidigital number, since it uses as much as digits as its factorization.
221131103211307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 28.
Adding to 221131103211307 its reverse (703112301131122), we get a palindrome (924243404342429).
The spelling of 221131103211307 in words is "two hundred twenty-one trillion, one hundred thirty-one billion, one hundred three million, two hundred eleven thousand, three hundred seven".
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