22114040119 has 2 divisors, whose sum is σ = 22114040120. Its totient is φ = 22114040118.

The previous prime is 22114040099. The next prime is 22114040141. The reversal of 22114040119 is 91104041122.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-22114040119 is a prime.

It is a super-3 number, since 3×22114040119³ (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 22114040093 and 22114040102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (22114040149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11057020059 + 11057020060.

It is an arithmetic number, because the mean of its divisors is an integer number (11057020060).

Almost surely, 2^22114040119 is an apocalyptic number.

22114040119 is a deficient number, since it is larger than the sum of its proper divisors (1).

22114040119 is an equidigital number, since it uses as much as digits as its factorization.

22114040119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

The spelling of 22114040119 in words is "twenty-two billion, one hundred fourteen million, forty thousand, one hundred nineteen".