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2211431111111 is a prime number
BaseRepresentation
bin100000001011100011100…
…100001101100111000111
321211102002102210010222002
4200023203210031213013
5242213002331023421
64411530055255515
7315525216203435
oct40134344154707
97742072703862
102211431111111
11782954234a52
122b870b97a59b
131306c9bc3101
1479068bc3d55
153c7cec9cb0b
hex202e390d9c7

2211431111111 has 2 divisors, whose sum is σ = 2211431111112. Its totient is φ = 2211431111110.

The previous prime is 2211431111081. The next prime is 2211431111159. The reversal of 2211431111111 is 1111111341122.

It is a m-pointer prime, because the next prime (2211431111159) can be obtained adding 2211431111111 to its product of digits (48).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2211431111111 is a prime.

2211431111111 is a modest number, since divided by 1111111 gives 221143 as remainder.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2211431611111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1105715555555 + 1105715555556.

It is an arithmetic number, because the mean of its divisors is an integer number (1105715555556).

Almost surely, 22211431111111 is an apocalyptic number.

2211431111111 is a deficient number, since it is larger than the sum of its proper divisors (1).

2211431111111 is an equidigital number, since it uses as much as digits as its factorization.

2211431111111 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48, while the sum is 20.

Adding to 2211431111111 its reverse (1111111341122), we get a palindrome (3322542452233).

The spelling of 2211431111111 in words is "two trillion, two hundred eleven billion, four hundred thirty-one million, one hundred eleven thousand, one hundred eleven".