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2212212000121 is a prime number
BaseRepresentation
bin100000001100010010000…
…111000100010101111001
321211111002212011102022021
4200030102013010111321
5242221102233000441
64412135352354441
7315553450512664
oct40142207042571
97744085142267
102212212000121
11783215002472
122b88a93a5a21
131307c2914406
14791007b66db
153c8285ec3d1
hex203121c4579

2212212000121 has 2 divisors, whose sum is σ = 2212212000122. Its totient is φ = 2212212000120.

The previous prime is 2212212000109. The next prime is 2212212000139. The reversal of 2212212000121 is 1210002122122.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1788197445225 + 424014554896 = 1337235^2 + 651164^2 .

It is a cyclic number.

It is not a de Polignac number, because 2212212000121 - 27 = 2212211999993 is a prime.

It is a super-3 number, since 3×22122120001213 (a number of 38 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2212212000095 and 2212212000104.

It is not a weakly prime, because it can be changed into another prime (2212212000161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1106106000060 + 1106106000061.

It is an arithmetic number, because the mean of its divisors is an integer number (1106106000061).

Almost surely, 22212212000121 is an apocalyptic number.

It is an amenable number.

2212212000121 is a deficient number, since it is larger than the sum of its proper divisors (1).

2212212000121 is an equidigital number, since it uses as much as digits as its factorization.

2212212000121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 2212212000121 its reverse (1210002122122), we get a palindrome (3422214122243).

The spelling of 2212212000121 in words is "two trillion, two hundred twelve billion, two hundred twelve million, one hundred twenty-one", and thus it is an aban number.