Base | Representation |
---|---|
bin | 1100111000011010000… |
… | …0111001011111001001 |
3 | 210011012210012000221022 |
4 | 3032012200321133021 |
5 | 12111210311244423 |
6 | 245355221122225 |
7 | 21663010560665 |
oct | 3160640713711 |
9 | 704183160838 |
10 | 221300103113 |
11 | 85942158a01 |
12 | 36a80b59375 |
13 | 17b3a16999b |
14 | a9d4d138a5 |
15 | 5b53400dc8 |
hex | 33868397c9 |
221300103113 has 2 divisors, whose sum is σ = 221300103114. Its totient is φ = 221300103112.
The previous prime is 221300103109. The next prime is 221300103137. The reversal of 221300103113 is 311301003122.
221300103113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 156363303184 + 64936799929 = 395428^2 + 254827^2 .
It is a cyclic number.
It is not a de Polignac number, because 221300103113 - 22 = 221300103109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 221300103091 and 221300103100.
It is not a weakly prime, because it can be changed into another prime (221300103413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110650051556 + 110650051557.
It is an arithmetic number, because the mean of its divisors is an integer number (110650051557).
Almost surely, 2221300103113 is an apocalyptic number.
It is an amenable number.
221300103113 is a deficient number, since it is larger than the sum of its proper divisors (1).
221300103113 is an equidigital number, since it uses as much as digits as its factorization.
221300103113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 221300103113 its reverse (311301003122), we get a palindrome (532601106235).
Subtracting 221300103113 from its reverse (311301003122), we obtain a palindrome (90000900009).
The spelling of 221300103113 in words is "two hundred twenty-one billion, three hundred million, one hundred three thousand, one hundred thirteen".
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