22131114350053 has 4 divisors (see below), whose sum is σ = 22132229793228. Its totient is φ = 22129998906880.

The previous prime is 22131114350039. The next prime is 22131114350063. The reversal of 22131114350053 is 35005341113122.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4680961583809 + 17450152766244 = 2163553^2 + 4177338^2 .

It is a cyclic number.

It is not a de Polignac number, because 22131114350053 - 2⁵ = 22131114350021 is a prime.

It is a super-2 number, since 2×22131114350053² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 22131114349997 and 22131114350024.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (22131114350003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 557691826 + ... + 557731507.

It is an arithmetic number, because the mean of its divisors is an integer number (5533057448307).

Almost surely, 2^{22131114350053} is an apocalyptic number.

It is an amenable number.

22131114350053 is a deficient number, since it is larger than the sum of its proper divisors (1115443175).

22131114350053 is a wasteful number, since it uses less digits than its factorization.

22131114350053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1115443174.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 22131114350053 its reverse (35005341113122), we get a palindrome (57136455463175).

The spelling of 22131114350053 in words is "twenty-two trillion, one hundred thirty-one billion, one hundred fourteen million, three hundred fifty thousand, fifty-three".