Base | Representation |
---|---|
bin | 1010000100001000001000… |
… | …11001101110101110000001 |
3 | 2220100210122221111002222121 |
4 | 11002010010121232232001 |
5 | 10400102404311030423 |
6 | 115023152521404241 |
7 | 4442662406560420 |
oct | 502040431565601 |
9 | 86323587432877 |
10 | 22132040330113 |
11 | 706316687018a |
12 | 2595407639681 |
13 | c47072347b4c |
14 | 5672a716d2b7 |
15 | 285a89da445d |
hex | 14210466eb81 |
22132040330113 has 8 divisors (see below), whose sum is σ = 25295327556800. Its totient is φ = 18969144898320.
The previous prime is 22132040330093. The next prime is 22132040330129. The reversal of 22132040330113 is 31103304023122.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-22132040330113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (22132040330143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 97827663 + ... + 98053636.
It is an arithmetic number, because the mean of its divisors is an integer number (3161915944600).
Almost surely, 222132040330113 is an apocalyptic number.
It is an amenable number.
22132040330113 is a deficient number, since it is larger than the sum of its proper divisors (3163287226687).
22132040330113 is a wasteful number, since it uses less digits than its factorization.
22132040330113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 195897447.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 22132040330113 its reverse (31103304023122), we get a palindrome (53235344353235).
The spelling of 22132040330113 in words is "twenty-two trillion, one hundred thirty-two billion, forty million, three hundred thirty thousand, one hundred thirteen".
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